All-America Football Conference (AAFC) Standings (1946-1949)


Eastern Division
Team
W
L
T
PCT.
New York Yankees
10
3
1
0.769
Brooklyn Dodgers
3
10
1
0.231
Buffalo Bisons
3
10
1
0.231
Miami Seahawks
3
11
0
0.154
Western Division
Cleveland Browns
12
2
0
0.857
San Francisco 49ers
9
5
0
0.643
Los Angeles Dons
7
5
2
0.583
Chicago Rockets
5
6
3
0.455
Championship: Cleveland 14, New York 9
         
Eastern Division
Team
W
L
T
PCT.
New York Yankees
11
2
1
0.846
Buffalo Bills
8
4
2
0.667
Brooklyn Dodgers
3
10
1
0.231
Baltimore Colts
2
11
1
0.154
Western Division
Cleveland Browns
12
1
1
0.923
San Francisco 49ers
8
4
2
0.667
Los Angeles Dons
7
7
0
0.500
Chicago Rockets
1
13
0
0.071
Championship: Cleveland 14, New York 3
         
Eastern Division
Team
W
L
T
PCT.
Buffalo Bills
7
7
0
0.500
Baltimore Colts
7
7
0
0.500
New York Yankees
6
8
0
0.429
Brooklyn Dodgers
2
12
0
0.143
Western Division
Cleveland Browns
14
0
0
1.000
San Francisco 49ers
12
2
0
0.857
Los Angeles Dons
7
7
0
0.500
Chicago Rockets
1
13
0
0.071
Eastern Division Playoff: Buffalo 28, Baltimore 17
Championship: Cleveland 49, Buffalo 7
         
Team
W
L
T
PCT.
Cleveland Browns
9
1
2
0.900
San Francisco 49ers
9
3
0
0.750
Brooklyn-NY Yankees
8
4
0
0.667
Buffalo Bills
5
5
2
0.500
Chicago Hornets
4
8
0
0.333
Los Angeles Dons
4
8
0
0.333
Baltimore Colts
1
11
0
0.083
Playoffs: Cleveland 31, Buffalo 21; San Francisco 17, Brooklyn-New York 7
Championship: Cleveland 21, San Francisco 7

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